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38f^2-25f=0
a = 38; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·38·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*38}=\frac{0}{76} =0 $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*38}=\frac{50}{76} =25/38 $
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